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It doesn't matter what the layout is, the question is the same even if i use different blueprint.
What matter is the amount of item that were used on that blueprint .
(btw, the blue chest thing is equalizer chest, a mod).
Now, i need a couple of this layout. Currently need 12 of those thing in my outpost.
Because math was a bit wonky on the fly on my head. I thought, i can use arithmetic combinator to count x amount of item i need.
So i made this constant + arithmetic + request + smart chest
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What it does is simply :
Each Constant combinator is where i put the base number of each item, i need 80 fast inserter on base blueprint, multiply by 12, i need 960 fast inserter.
The smart inserter will pull from request chest, and will check whether the item is equal with arithmetic signal, and stop pulling if the amount is equal.
Sure i can do this in one request chest the usual way, ordering 960 inserter and other item.
Or i can put another 11 request chest then copy the request from one chest to another.
But i want to avoid calculating stuff, and different outpost need different amount of things. So it's easier to use arithmatic to do the calculating how much certain item is needed for x blueprint copies.
So,.the question is,..how do i simplify this setup ? I barely grasp the concept of combinator, only use them for simple stuff like redirecting pump of chemical plant, turning off steam engine when not needed.
Never use connstant and arithmetic combinator before this.