Need help replace items in all recipes

[BOFan80]

I need your help, i waant to replace all ironplates in recipes with an item who called carbon-plate.

i tried different solutions, wich i found, but no ones helps.

I tried to wrote a script but there is an error. pls help me

script is saved in control.lua

Code: Select all

script.on_init 
(function() ReplaceAllIngredientItemWithItem(iron-plate, carbon-plate)
	for i, recipe in pairs(data.raw["recipe"]) do
		for v, ingredient in pairs(data.raw["recipe"][recipe.name].ingredients) do
			if ingredient.name == iron-plate then
				RemoveFromRecipe(recipe.name,iron-plate)
				AddToRecipe(recipe.name, carbon-plate, ingredient.amount)
			elseif ingredient[1] == iron-plate then
				RemoveFromRecipe(recipe.name,iron-plate)
				AddToRecipe(recipe.name, carbon-plate, ingredient[2])
			end
		end
	end)

ore is there a solution without script.

[Qon]

Variable "data" is available at data stage, in data.lua, not in control stage in control.lua.
Also, "script" is only available in control stage. Take the code inside the function and just execute it directly.

[BOFan80]

Variable "data" is available at data stage, in data.lua, not in control stage in control.lua.
Also, "script" is only available in control stage. Take the code inside the function and just execute it directly.

Thx

i copy this

Code: Select all

function ReplaceAllIngredientItemWithItem (iron-plate , carbon-plate)
	for i, recipe in pairs(data.raw["recipe"]) do
		for v, ingredient in pairs(data.raw["recipe"][recipe.name].ingredients) do
			if ingredient.name == iron-plate then
				RemoveFromRecipe(recipe.name,iron-plate)
				AddToRecipe(recipe.name, carbon-plate, ingredient.amount)
			elseif ingredient[1] == iron-plate then
				RemoveFromRecipe(recipe.name,iron-plate)
				AddToRecipe(recipe.name, carbon-plate, ingredient[2])
			end
		end
	end

in to my data.lua. but it shows allways an error

did i forget something?

[Pi-C]

did i forget something?

Handling recipes is something just short of dark magic.

There are different places in a recipe where ingredients, results etc. can be set. In the most simple case, it will be at the root, like recipe.ingredients. But a recipe could have difficulty (IIRC, if there is at least one difficulty defined, that will be used at the end of the data stage, and the values at the root level will be discarded). So you must check recipe.normal.ingredients and recipe.expensive.ingredients as well.

Also, ingredients can be in either short or long format, so you must check each ingredient for both variants.

This should work:

Code: Select all

local function replace_in_difficulty(ingredients, old, new)
  if not (ingredients and old and new) then
    return
  end

  for i, ingredient in pairs(ingredients) do
    if ingredient[1] == old then
      ingredient[1] = new
    elseif ingredient.name == old then
      ingredient.name = new
    end
  end
end

function ReplaceAllIngredientItemWithItem(old, new)
  for i, recipe in pairs(data.raw.recipe) do
    replace_in_difficulty(recipe.ingredients, old, new)
    replace_in_difficulty(recipe.normal and recipe.normal.ingredients, old, new)
    replace_in_difficulty(recipe.expensive and recipe.expensive.ingredients, old, new)
  end
end

ReplaceAllIngredientItemWithItem("iron-plate", "carbon-plate")

[BOFan80]

Thx u help me lot