burner productivity
burner productivity
In a mod I want to present a kind of recipe for the production of steam. But I can't find anything about how much water an entity of the type "boiler" will turn into steam in which time.
Mods: ingteb, ixuClock, ixuAutoSave, NoCheating, hardCrafting (Maintainer) and more
Desperately tried to implement redo
Desperately tried to implement redo
- Deadlock989
- Smart Inserter
- Posts: 2529
- Joined: Fri Nov 06, 2015 7:41 pm
Re: burner productivity
Oh sorry, I wasn't precise enough: I need this information inside my mod.
Mods: ingteb, ixuClock, ixuAutoSave, NoCheating, hardCrafting (Maintainer) and more
Desperately tried to implement redo
Desperately tried to implement redo
- Deadlock989
- Smart Inserter
- Posts: 2529
- Joined: Fri Nov 06, 2015 7:41 pm
Re: burner productivity
You're going to have spell out what it is you're trying to do in considerably more detail, we can't guess.
Re: burner productivity
The screenshot shows what I want to display. The line with the steam is marked. The values here are currently hardwired and the producers do not show a factor yet.
Probably a mod that defines boiler is displayed wrong, because I did not get the values from any prototypes.
It is this mod btw: https://mods.factorio.com/mod/ingteb
Probably a mod that defines boiler is displayed wrong, because I did not get the values from any prototypes.
It is this mod btw: https://mods.factorio.com/mod/ingteb
Mods: ingteb, ixuClock, ixuAutoSave, NoCheating, hardCrafting (Maintainer) and more
Desperately tried to implement redo
Desperately tried to implement redo
- Deadlock989
- Smart Inserter
- Posts: 2529
- Joined: Fri Nov 06, 2015 7:41 pm
Re: burner productivity
Right. It is a formula, derived from the target_temperature and energy_consumption properties on the boiler and from the heat_capacity property and the current temperature of the fluid (which is usually, but not necessarily, the default temperature). It costs heat_capacity joules to heat 1 unit of fluid by 1 degree. In water's case that is 0.2 kJ. The boiler wants to get the water from its current temperature (usually the default) to its target, so that is 165-15 = 150 degree increase: that takes 150 * 0.2 = 30 kJ. The boiler can consume a maximum 1.8MW = 1800 kJ per second so its maximum flow rate is 1800 / 30 = 60 units/s.
Re: burner productivity
Thank you. That sounds like challenge.
Mods: ingteb, ixuClock, ixuAutoSave, NoCheating, hardCrafting (Maintainer) and more
Desperately tried to implement redo
Desperately tried to implement redo