Circuit Conditions - Train Station help

[ritzcrackers]

Hi there,

I have a railway station and I am trying to get an inserter to load some ammo and some repair packs, but only if they are below a certain amount. I'm using decider combinators to output a signal A = 1, if either condition is true. However it doesn't seem to be working, though I think it should. Can anybody lend their expertise? I've attached photos so you can see exactly what I am doing.

The train just sits at its stop and does not load.

I'm going a bit nuts with this as it did work once, but now it just fails to work at all! I feel like I a missing something very simple.

Cheers,

ritz

20171015130018_1.jpg (179.94 KiB) Viewed 6804 times

20171015130013_1.jpg (144.99 KiB) Viewed 6804 times

20171015130022_1.jpg (109.32 KiB) Viewed 6804 times

20171015130024_1.jpg (120.46 KiB) Viewed 6804 times

20171015130026_1.jpg (205.38 KiB) Viewed 6804 times

[Loewchen]

Post the save please.

[Jap2.0]

Both conditions are true, so both combinators are outputing 1 on A, which if I remember correctly will mean the inserter recieves a signal of 2 on A. Since this isn't equal to 1, it is off. I think what you want to do is a bit more complicated with setting the filter and stuff.

[vortex1967]

Hi ritzcrackers,

An easy solution would be:

Decider Combinators:
Piercing Round combinator – change output from A to Piercing Round.
Repair Pack combinator – change output from A to Repair Pack.

Stack Inserter:
Replace with a Stack Filter Inserter – change 'Mode of operation' to “Set Filters”

Now when the train arrives only the item that is low will be loaded.
If both items are low then each will be loaded in turn.

If the wagon has it's contents limited via the red cross, set the quantity of each item in the decider combinators
to 15 – 20 items less than the stack size for that item(if your not wanting more than a stack, so the inserter isn't left holding an item).
If the wagon doesn't have it's contents limited via the red cross, remember not to set the locomotive to manual mode
or add another wagon(train will switch to manual mode)while the train is parked at the stop or the wagon will fill up.

[ritzcrackers]

Thanks everybody!

Hi ritzcrackers,<br style="text-shadow: none;"><br style="text-shadow: none;">An easy solution would be:<br style="text-shadow: none;"><br style="text-shadow: none;">Decider Combinators:<br style="text-shadow: none;">Piercing Round combinator – change output from A to Piercing Round.<br style="text-shadow: none;">Repair Pack combinator – change output from A to Repair Pack.<br style="text-shadow: none;"><br style="text-shadow: none;">Stack Inserter:<br style="text-shadow: none;">Replace with a Stack Filter Inserter – change 'Mode of operation' to “Set Filters”<br style="text-shadow: none;"><br style="text-shadow: none;">Now when the train arrives only the item that is low will be loaded.<br style="text-shadow: none;">If both items are low then each will be loaded in turn.<br style="text-shadow: none;"><br style="text-shadow: none;">If the wagon has it's contents limited via the red cross, set the quantity of each item in the decider combinators<br style="text-shadow: none;">to 15 – 20 items less than the stack size for that item(if your not wanting more than a stack, so the inserter isn't left holding an item).<br style="text-shadow: none;">If the wagon doesn't have it's contents limited via the red cross, remember not to set the locomotive to manual mode<br style="text-shadow: none;">or add another wagon(train will switch to manual mode)while the train is parked at the stop or the wagon will fill up.

I ended up taking this approach and it works better than I had originally envisioned.

[Engimage]

Both conditions are true, so both combinators are outputing 1 on A, which if I remember correctly will mean the inserter recieves a signal of 2 on A. Since this isn't equal to 1, it is off. I think what you want to do is a bit more complicated with setting the filter and stuff.

This
You have to replace enabled condition on an inserters with A > 0 instead of A=1 as if both conditions are true both combinators output A=1 giving a total value of A=2.

[vortex1967]

Hi all,

Sorry in advanced for the long post (inside the spoiler).

When there are multiple items in a wagon and in a chest with one stack/filter inserter inserting into the wagon.
Setting both Decider Combinators(D/C's) to output 'A' with a value of '1' when an item in the wagon the D/C's are
detecting is below a set quantity (as in ritzcracker's OP set up) has the following problems (inside the spoiler).

Problems with outputting value of A

Setting the condition in the stack inserter to 'A=1':
When both items are low – The inserter is seeing 'A' with a value of '2'. Condition is False. Will never activate.
and
When one item is low – The inserter is seeing 'A' with a value of '1'. Condition is True. Which item?
The inserter doesn't know which item is low.
Over time the wagon would become clogged with one item because there is no distinction between items.

Setting the condition in the stack inserter to 'A>0':
When both items are low – The inserter is seeing 'A' with a value of '2'. Condition is True.
Both items are required. How many of each item is required? Which item is lower?
Which item has reached a D/C's condition?
Over time the wagon would become clogged with one item because there is no distinction between items.
and
When one item is low – The inserter is seeing 'A' with a value of '1'. Condition is True. Which item is low?
The inserter doesn't know which item is low.
Again over time the wagon would become clogged with one item because there is no distinction between items.

When the stack inserter condition is true it removes from the chest the item that is at the end of the stacks not necessarily the item that is required.
If that particular item is replenished into the chest faster than the stack inserter can insert into the wagon then that item will always be put into the wagon.

Even just setting filters as I suggested has it's drawbacks as well.
Because the D/C's are set to output when an item is low, when a train isn't at the stop the D/C's are detecting no items
so they output, which activates the inserter, when the train arrives again the inserter performs one cycle and inserts a
particular item(quantity equivalent to the current stack filter inserter or filter inserter researched stack bonus)into the
wagon even if that item isn't lower than the value set to be detected in a D/C.
Over time the wagon would become clogged with one item.

The only way around it is to isolate the inserter from the D/C's until the train is parked at the stop (in automatic mode).
Now that trains have a unique ID number (don't know what version of Factorio it was implemented) that is greater
than '1' after the first train is placed (with a default letter of 'T') we can set a D/C to 'T>1' output 'T' with 'Input count'
selected. Wired exactly the same as the D/C's that detect the contents of the wagon.
'Read stopped train' has to be selected in the stop so the train ID is outputted.

Another D/C set to 'Anything>1' output 'Everything' with '1' selected is then used that isolates the inserter from the
D/C's that are detecting the train ID and the quantity and type of item in the wagon.
Only when a train arrives at the stop (that has an ID of '2' or higher) does the 'Anything>1' output 'Everything' become True.
Allowing the output from the D/C's to get to the inserter.

Now items will not be inserted into the wagon when a train returns unless items are low, even if the train is set to manual mode at the stop.
If the train you are using is your first train and it's the first time it has been placed it will have an ID of '1'.
Pick it up and place it again it should now have an ID of '2'. Any train placed from now on will not use the ID of '1'.

The following images hopefully are clear enough to see how to set up what I just explained.

Train Stop-H.jpg (447.8 KiB) Viewed 6670 times

Train Detector-H.jpg (325.94 KiB) Viewed 6670 times

Inserter Isolator-H.jpg (324.96 KiB) Viewed 6670 times

[ritzcrackers]

Hi all,

Sorry in advanced for the long post (inside the spoiler).....

Hey vortex1967, thanks for delving deeper in to this! you've further increased my understanding of this whole thing with you explanation and experimentation.