Having difficulty changing the recipe of the T3 assembler

[UntouchedWagons]

I want to make the tier 3 assembler use only one tier 2 assembler but I'm having a hell of a time doing it. If I put

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data.raw.recipe["assembling-machine-3"].ingredients[1][2] = 1

That changes to number of speed modules needed even though speed modules are the first thing defined as an ingredient in recipe.lua. If I change the [1][2] to [1][1] or [1][3] Factorio throws a fit. What gives?

[DaveMcW]

You want [2][1].

[prg]

You want [2][1].

No, [2][2].

[DaveMcW]

Right.

If you want to be clearer/safer, you can do a loop:

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for _, ingredient in pairs (data.raw.recipe["assembling-machine-3"].ingredients) do
  if (ingredient[1] == "assembling-machine-2") then
    ingredient[2] = 1
  end
end

[keyboardhack]

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data.raw.recipe["assembling-machine-3"]

returns

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{
    type = "recipe",
    name = "assembling-machine-3",
    enabled = false,
    ingredients =
    {
      {"speed-module", 4},
      {"assembling-machine-2", 2}
    },
    result = "assembling-machine-3"
}

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data.raw.recipe["assembling-machine-3"].ingredients

returns

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{
      {"speed-module", 4},
      {"assembling-machine-2", 2}
}

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data.raw.recipe["assembling-machine-3"].ingredients[1]

returns

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 {
      "speed-module",
      4
}

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data.raw.recipe["assembling-machine-3"].ingredients[1][2]

returns

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4

so

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data.raw.recipe["assembling-machine-3"].ingredients[1]

gets you the first ingredients name and the amount of them used

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data.raw.recipe["assembling-machine-3"].ingredients[2]

gives you the second ingredients name and amount.

so you probably want to do

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data.raw.recipe["assembling-machine-3"].ingredients[2][2]

[UntouchedWagons]

You want [2][1].

No, [2][2].

Thanks

All that stuff

How do you make the game print that stuff? I tried

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/c print(data.raw.recipe["assembling-machine-3"])

and it said that data didn't exist or something.

[oLaudix]

You can't print it like that.

You need to use something like this.

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/c game.player.print(game.player.force.recipes["assembling-machine-3"].ingredients[1].name)
/c game.player.print(game.player.force.recipes["assembling-machine-3"].ingredients[1].amount)

Moreover:

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/c game.player.print(game.player.force.recipes["assembling-machine-3"]

nor

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/c game.player.print(game.player.force.recipes["assembling-machine-3"].ingredients[1]

can be printed since you cant print userdata nor table.
If you want to print recipe ingredients do smth like this:

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/c 
for i,ingredient in pairs(game.player.force.recipes["assembling-machine-3"].ingredients) do
	  game.player.print(ingredient.name .. " - " .. ingredient.amount)
end

[prg]

You can't print it like that.

Not from the console in a running game, but from data*.lua.

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print(serpent.block(data.raw.recipe["assembling-machine-3"].ingredients))

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{
  {
    "speed-module",
    4
  } --[[table: 0x2c28580]],
  {
    "assembling-machine-2",
    2
  } --[[table: 0x2c28610]]
} --[[table: 0x2c284f0]]

[orzelek]

Where do you get output from print thats running in data phase?

You can also use serpent.block from console to print whole recipe.

[prg]

Where do you get output from print thats running in data phase?

That's going to stdout, so you can see it nicely formatted in the terminal you're running Factorio in. (Or if it's too much output, like when you're dumping all of data.raw, redirect it to a file or pipe it to less or something)