Hello fellow engineers,
(Playing space age DLC, no mods)
XY:
I am producing power by converting sulfuric acid to steam on vulcanus (duh). My current setup requires a constant supply of 3.200 sulfuric acid per second to run all steam turbines at 100 % capacity.
Like all of you fine engineers, I have never once forgotten to take care of my power supply while on another planet so none of them ever experienced a blackout. However to prevent this highly unlikely scenario, i am setting up a warning system using circuit magic.
This leads me to the pumpjacks. I want to broadcast a global warning as soon as the pumpjack fields connected to my power supply produce less than 2x the consumption per second of the energy generation.
The only value I see that pumpjacks allow me use for this is "expected resources" - but what is that exactly? Right there in the same tooltip is says it is producing an entirely different number to the expected resources.
For reference, one of my pumpjacks on sulfuric acid:
Pumpjack (Rare)
Mining speed: 2/s (+100%)
1.8k/s
Productivity: +100%
Resource drain: 66%
Expected resources: 459/s
Inserted 2x Speed module 3 (normal quality)
No beacons
[irrelevant data omitted]
What exactly is "expected resources" on a pumpjack? I have accumulated more hours in this game than I'd like to admit and I know that pumpjacks never run out and at a certain point just produce a certain minimum output. But regarding this I'm stumped. Now that I'm thinking about, my strategy for resources that are extracted by pumpjacks is just: place as many as possible - as I have no idea how to calculate how many/much is truly needed to statisfy consumption.
Thanks for your help.
Pumpjacks - expected resources logic
Re: Pumpjacks - expected resources logic
Expected resources is the output (in fluid per second) of a normal pumpjack with no bonuses at all.
You will have to multiply all your bonuses to that in an arithmetic combinator if you want it to match what you have.
In your case the calculation is:
459 (pumpjack signal) * (1 + 100/100 speed) * (1 + 100/100 productivity) = 1836.
You will have to multiply all your bonuses to that in an arithmetic combinator if you want it to match what you have.
In your case the calculation is:
459 (pumpjack signal) * (1 + 100/100 speed) * (1 + 100/100 productivity) = 1836.
Re: Pumpjacks - expected resources logic
I appreciate your comprehensive explanation, thank you. It reproduced your formula successfully.DaveMcW wrote: ↑Sun Nov 24, 2024 1:26 am Expected resources is the output (in fluid per second) of a normal pumpjack with no bonuses at all.
You will have to multiply all your bonuses to that in an arithmetic combinator if you want it to match what you have.
In your case the calculation is:
459 (pumpjack signal) * (1 + 100/100 speed) * (1 + 100/100 productivity) = 1836.