Search found 6 matches
- Sun Apr 10, 2016 4:46 pm
- Forum: General discussion
- Topic: Perfectly optimal solar network
- Replies: 18
- Views: 94922
Re: Perfectly optimal solar network
Sorry Fraktal, I should have been more specific. I was answering uthul1 : Ratio Solar Panels : Accumulators = 20 : 21 This is the false result. Just tu make sure nothing changed, I did a test this afternoon with 1000 solar panels, 840 accus, and 140 radars, and the 84 accus for 100 solar panels sho...
- Sun Apr 10, 2016 3:34 pm
- Forum: General discussion
- Topic: Perfectly optimal solar network
- Replies: 18
- Views: 94922
Re: Perfectly optimal solar network
Sorry, but your calculation has false hypotheses, which lead you to wrong result :) This is the correct way to do it : https://forums.factorio.com/viewtopic.php?f=5&t=5594. This is a bit of an archived topic. Cilya and I have essentially the same results approached from different directions. Hi...
- Tue Aug 05, 2014 10:36 am
- Forum: General discussion
- Topic: Perfectly optimal solar network
- Replies: 18
- Views: 94922
Re: Perfectly optimal solar network
...0.43 P *0.7*416.66 = 140* P seconds. I think there's a small mistake here. I get 125.4 P second. You're right, I'll fix that right away. and you lost me here: though they are at full power for only 52s during the night. The only time accumulators provide P is for the entire duration of night, wh...
- Mon Aug 04, 2014 9:09 pm
- Forum: General discussion
- Topic: Perfectly optimal solar network
- Replies: 18
- Views: 94922
Re: Perfectly optimal solar network
Last set of mathematics. I've solved for the exact optimal number of solar arrays and accumulators for any network. The only input needed is still P. The units of P are MW. Start with the equation for the number of solar panels n_s n_s=23.8*P Round n_s up to the nearest whole number, since n_s is th...
- Mon Aug 04, 2014 8:11 pm
- Forum: General discussion
- Topic: Perfectly optimal solar network
- Replies: 18
- Views: 94922
Re: Perfectly optimal solar network
I just made a perfect radar array. In practice, the numbers a bit off, especially for small networks. A radar requires 300 kW of power (0.3 MW). Using the mentioned equations, it needs 7.14 solar panels and 8.4 accumulators to function. 7.14 is an absolute minimum, so I had to round up to 8 solar pa...
- Mon Aug 04, 2014 10:01 am
- Forum: General discussion
- Topic: Perfectly optimal solar network
- Replies: 18
- Views: 94922
Perfectly optimal solar network
So I was bothered by not knowing the right amount of solar panels and accumulators that I needed to keep my factory running, so I did some math to figure out the optimal number for any electrical network. The only input you need is the standard consumption of an electrical network (Watts) when not c...