How would I calculate daily "usable" power from these numbers? With the old 416.6 second day/night cycle, it took 238.095 solar panels and 200 accumulators to get 10 MW of daily usable power. So (total solar panel output) x 0.7 = daily usable power.


From the math post above:

Solar panels ...

Thanks, this helped.

Converting it to a simple thought experiment:

Assume you have an acc+solar setup where all power is fully consumed, i.e. accumulators just barely drain fully overnight and just barely reach full charge at the end of the day.
If solar power yield increases 2x, and the day ...

Thanks for doing this!

Intuitively, Vulcanus should require 1/4 as many solar panels. If the days have the same "shape", then the length of the day should only affect the amounts, not the ratios. (Right?)

One thing that wasn't clear to me in the math is why the "energy storage required" value is ...