Factorio Forums

Posted: **Wed May 24, 2017 1:18 pm**

Is it possible to make a fluid recipe such that 100 of A -> 100 of A at 99% of the time and 100 of A -> 99 of A at 1 % of the time?

Alternatively, 100 of A -> 100 of B at 99% and 100 of A -> (99 of B and 1 of C) at 1% of the time?

Both of the above are not equivalent to (100 of A -> 99 of B and 1 of C) or (100 of A -> 99 of A), which are fixed ratios.

Posted: **Wed May 24, 2017 2:08 pm**

I think you are looking for what was suggested here?

viewtopic.php?f=23&t=47597&p=276271#p276271

Posted: **Wed May 24, 2017 2:40 pm**

see here http://lua-api.factorio.com/latest/Conc ... ml#Product

Posted: **Wed May 24, 2017 3:22 pm**

Helfima wrote:see here http://lua-api.factorio.com/latest/Conc ... ml#Product

I'm aware of all of that. I've used that even before it was documented. What I am asking doesn't seem do able from all that I know.

Arch666Angel wrote:I think you are looking for what was suggested here?

viewtopic.php?f=23&t=47597&p=276271#p276271

If that is the case, what I want is not possible with the current probabilistic implementation as outputs are rolled independently.

Posted: **Fri May 26, 2017 2:24 am**

I have solved my own problem.

For the first case, 100 of A -> 100 of A at 99% of the time and 100 of A -> 99 of A at 1 % of the time, make the following recipe.
100 of A -> 99 of A + 1 of A at probability = 99%

Code: Select all

ingredients =
{
	{type="fluid", name="A", amount=100},
},
results=
{
	{type="fluid", name="A", amount=99},
	{type="fluid", name="A", amount=1, probability=0.99},
},

For the second case, 100 of A -> 100 of B at 99% and 100 of A -> (99 of B and 1 of C) at 1% of the time, make the following recipe.
100 of A -> 99 of B + 1 of B at probability = 99% + 1 of C at probability = 1%

Code: Select all

ingredients =
{
	{type="fluid", name="A", amount=100},
},
results=
{
	{type="fluid", name="B", amount=99},
	{type="fluid", name="B", amount=1, probability=0.99},
	{type="fluid", name="C", amount=1, probability=0.01},
},

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