Version 0.16.50

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Merssedes
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Re: Version 0.16.50

Post by Merssedes » Sat Jun 23, 2018 7:48 am

Liono2010 wrote:I am not sure what does this mean.
Your assumption "You are looking at everything in the form of binary" is wrong :)

pleegwat
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Re: Version 0.16.50

Post by pleegwat » Sat Jun 23, 2018 10:14 am

Liono2010 wrote:
Merssedes wrote:
Liono2010 wrote:
Merssedes wrote:(2-2).(2^(2^2)).((2+2*2*2)^2)/2
:)
WOW! That was really a nice calculation. You are looking at everything in the form of binary(2). Are you from Matrix? :D
Wrong assumption leads to wrong answer :)
I am not sure what does this mean.
(2-2)=0
(2^(2^2))=2^4=16
((2+2*2*2)^2)/2=((2+8)^2)/2=(10^2)/2=100/2=50

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Liono2010
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Re: Version 0.16.50

Post by Liono2010 » Wed Jun 27, 2018 6:36 am

Merssedes wrote:
Liono2010 wrote:I am not sure what does this mean.
Your assumption "You are looking at everything in the form of binary" is wrong :)
Oh, okay I got that. But I saw only "2" in the expression so said the word "binary", even I know binary doesn't have the digit two.
pleegwat wrote:
Liono2010 wrote:
Merssedes wrote:
Liono2010 wrote:
Merssedes wrote:(2-2).(2^(2^2)).((2+2*2*2)^2)/2
:)
WOW! That was really a nice calculation. You are looking at everything in the form of binary(2). Are you from Matrix? :D
Wrong assumption leads to wrong answer :)
I am not sure what does this mean.
(2-2)=0
(2^(2^2))=2^4=16
((2+2*2*2)^2)/2=((2+8)^2)/2=(10^2)/2=100/2=50
This wasn't the thing I was asking about. However Merssedes already explained me.

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