Solar farm fit for huge bases
Posted: Wed Jun 21, 2017 10:02 pm
Hi everyone!
If you build a large factory (really huge), you probably hit one common problem - the performance (UPS). Solar panels are great way to make free energy with low performance drain. It is also fine to not use roboport or anything else - just the most dense pattern of solar panels and accumulators as you can place. It is allready tested that even for a factory which makes more than 2000 sci packs per minute of each specie (with full prod3 support) is not so complicated to build by running with personal robort.
So i designed following pattern...
No. accumulators/solar panels = 26/32 = 0.8125 = 0.967 × 0.84
Space efficiency = (32×9 + 26×4) / (32×9 + 26×4 + 4) = 98/99 ~ 98,99 %
Substations are attached in a horizontal way only. There is also a little bias from perfect ratio. You can deal with boths by adding a border
You have to build this border per a row with 41 substations in total and you obtain...
No. accumulators/solar panels = 1092/1300 = 0.84
Space efficiency = (1092×4 + 1300×9)/(1092×4 + 1300×9 + (41+1)×4) = 1339/1353 ~ 98,97 %
Average power = 42×1300 = 54.6 MW
... a perfect ratio with 1.03 % space efficiency loss in substations and the big pole. You can place these lines on yourself thanks to the big pole on the border. With 40 of these lines (which is nearby square) you obtain about 2GW power.
If you build a large factory (really huge), you probably hit one common problem - the performance (UPS). Solar panels are great way to make free energy with low performance drain. It is also fine to not use roboport or anything else - just the most dense pattern of solar panels and accumulators as you can place. It is allready tested that even for a factory which makes more than 2000 sci packs per minute of each specie (with full prod3 support) is not so complicated to build by running with personal robort.
So i designed following pattern...
No. accumulators/solar panels = 26/32 = 0.8125 = 0.967 × 0.84
Space efficiency = (32×9 + 26×4) / (32×9 + 26×4 + 4) = 98/99 ~ 98,99 %
Substations are attached in a horizontal way only. There is also a little bias from perfect ratio. You can deal with boths by adding a border
You have to build this border per a row with 41 substations in total and you obtain...
No. accumulators/solar panels = 1092/1300 = 0.84
Space efficiency = (1092×4 + 1300×9)/(1092×4 + 1300×9 + (41+1)×4) = 1339/1353 ~ 98,97 %
Average power = 42×1300 = 54.6 MW
... a perfect ratio with 1.03 % space efficiency loss in substations and the big pole. You can place these lines on yourself thanks to the big pole on the border. With 40 of these lines (which is nearby square) you obtain about 2GW power.