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I do not understand how percent works in an arithmetic combinator. Please explain me

42 ÷ 10 = 4 remainder 2

42 / 10 = 4
42 % 10 = 2

DaveMcW wrote:42 ÷ 10 = 4 remainder 2

42 / 10 = 4
42 % 10 = 2

What am I doing wrong? Why does not 2 come out?

DaveMcW wrote:42 ÷ 10 = 4 remainder 2

42 / 10 = 4
42 % 10 = 2

Why is not 10% coming output?

WIZ4 wrote:

DaveMcW wrote:42 ÷ 10 = 4 remainder 2

42 / 10 = 4
42 % 10 = 2

What am I doing wrong? Why does not 2 come out?

You are calculating 6 % 20, which results in 6 (6 / 20 = 0, remainder 6)
You need to swap them in the combinator to set it to 20 % 6, which results in 2 (20 / 6 = 3, remainder 2).

WIZ4 wrote:I do not understand how percent works in an arithmetic combinator. Please explain me

This is the remainder of the division, not percents.
Это остаток от деления, а не проценты.

Exactly. If you want 20% of the input you would multiply by .20

6 * .20 = 1.2

If you cannot do decimal, you could do more combinators:

6 * 20 / 100 = 1.2

It's not a percentage. It's called modulo:

https://en.wikipedia.org/wiki/Modulo_operation

nevniv wrote:Exactly. If you want 20% of the input you would multiply by .20

6 * .20 = 1.2

It's not possible directly with combinators. They operate with integers only. There should be two combinators as in your second example.

hitzu wrote:

nevniv wrote:6 * 20 / 100 = 1.2

There should be two combinators as in your second example.

Tip: always multiply before dividing. Integer division causes a loss of precision.

6 * 20 / 100 = 1 (result rounded down from 1.2)
6 / 100 * 20 = 0 (because 6/100 is rounded down to 0 first)

The % is not PERCENT.

it is like dividing by the givven number and return the remainings. There are only full numbers used like thet:
2 % 2 =0 remaining (2 / 2= 1which is just dumped, )
3 % 2 = 1 remaining (3 / 2 = 1which gets dumped again but now we get 1 remaining)
4 % 2 = 0 remining

I understand, thanks for explaining