What are /m units in asteroid density?
Posted: Sat Nov 30, 2024 2:20 pm
Spec'ing out an end-game ship. Final huge promethium asteroid density is 714/m. What does that mean?
My guess is 714 huge promethium asteroids / minute, but the width of a ship should play a part right? So a wider ship should encounter more asteroids. That 714/minute must assume a specific width of the ship. It also assumes a specific speed... so does that mean it'll actually encounter fewer asteroids by traveling faster? That's counter-intuitive.
Another option: 714 huge promethium asteroids / meter. Since I'm traveling at 150 km/s, that puts me at 107 million asteroids per second. That can't be right. And it doesn't consider the width of the ship.
Perhaps it's saying the density in that orbit from the star is 714/meter. That means in a giving 1m-wide ring around the star, there will be 714 huge promethium asteroids. The total area of that ring would be A=(pi*r*r - pi*(r-1)*(r-1)), and we could calculate how many of those 714 asteroids we will encounter by estimating the width of the ring we will pass through. But since we don't know our distance to the star (r), we can't calculate it.
My guess is 714 huge promethium asteroids / minute, but the width of a ship should play a part right? So a wider ship should encounter more asteroids. That 714/minute must assume a specific width of the ship. It also assumes a specific speed... so does that mean it'll actually encounter fewer asteroids by traveling faster? That's counter-intuitive.
Another option: 714 huge promethium asteroids / meter. Since I'm traveling at 150 km/s, that puts me at 107 million asteroids per second. That can't be right. And it doesn't consider the width of the ship.
Perhaps it's saying the density in that orbit from the star is 714/meter. That means in a giving 1m-wide ring around the star, there will be 714 huge promethium asteroids. The total area of that ring would be A=(pi*r*r - pi*(r-1)*(r-1)), and we could calculate how many of those 714 asteroids we will encounter by estimating the width of the ring we will pass through. But since we don't know our distance to the star (r), we can't calculate it.