Nope. I meant what I wrote, which is why I used kW/m2 instead of kWh/m2.DaveMcW wrote:That is 2 kilowatt-hours/m^2. You need to divide by 4 hours to get the average radiation, 0.5 kW/m^2.
However, my source had bad data. Our peak irradiance is more inline with OPs working value of 1kW during our summer.